and further
(48)

$\Phi _{4}={\frac {i[{\mathfrak {wE}}]}{\sqrt {1{\mathfrak {w}}^{2}}}}$,

Because F is an alternating matrix,
(49)

$w{\overline {\Phi }}=w_{1}\Phi _{1}+w_{2}\Phi _{2}+w_{3}\Phi _{3}+w_{4}\Phi _{4}=0$,

i.e. $\Phi$ is perpendicular to the vector to w; we can also write
(50)

$\Phi _{4}=i({\mathfrak {w}}_{x}\Phi _{1}+{\mathfrak {w}}_{y}\Phi _{2}+{\mathfrak {w}}_{z}\Phi _{3})$,

I shall call the spacetime vector $\Phi$ of the first kind as the Electric Rest Force.
Relations analogous to those holding between $wF,\ {\mathfrak {E,\ M,\ w}}$, hold amongst $wf,\ {\mathfrak {e,\ m,\ w}}$, and in particular wf is normal to w. The relation (C) can be written as
{C}

$wf=\epsilon wF$

The expression (wf) gives four components, but the fourth can be derived from the first three.
Let us now form the timespace vector 1st kind $\Psi =iwf^{*}$, whose components are
${\begin{array}{cccccccccc}\Psi _{1}&=&i(&&&w_{2}f_{34}&+&w_{3}f_{42}&+&w_{4}f_{23}),\\\Psi _{2}&=&i(&w_{1}f_{43}&&&+&w_{3}f_{14}&+&w_{4}f_{31}),\\\Psi _{3}&=&i(&w_{1}f_{24}&+&w_{2}f_{41}&&&+&w_{4}f_{12}),\\\Psi _{4}&=&i(&w_{1}f_{32}&+&w_{2}f_{13}&+&w_{3}f_{21}&&).\end{array}}$
Of these, the first three $\Psi _{1},\ \Psi _{2},\ \Psi _{3}$ are the x, y, zcomponents of the spacevector
(51)

${\frac {{\mathfrak {m}}[{\mathfrak {we}}]}{\sqrt {1{\mathfrak {w}}^{2}}}}$,

and further
(52)

$\Psi _{4}={\frac {i[{\mathfrak {wm}}]}{\sqrt {1{\mathfrak {w}}^{2}}}}$;

Among these there is the relation
(53)

$w{\overline {\Psi }}=w_{1}\Psi _{1}+w_{2}\Psi _{2}+w_{3}\Psi _{3}+w_{4}\Psi _{4}=0$,

which can also be written as