Page:Elements of the Differential and Integral Calculus - Granville - Revised.djvu/178

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In the following seven examples the equations are given in parametric form.

Find \tfrac{dy}{dx} and \tfrac{d^2 y}{dx^2} in each case:

16. x = 7 + t^2, y = 3 + t^2 - 3t^4. Ans. \frac{dy}{dx} = 1 - 6 t^2, \frac{d^2 y}{dx^2} = -6.
17. x = \cot t, y = \sin^3 t. Ans. \frac{dy}{dx} = -3 \sin^4 t \cos t, \frac{d^2 y}{dx^2} = 3 \sin^5 t (4 - 5 \sin^2 t).
18. x = a(\cos t + \sin t), y = a(\sin t - t \cos t). Ans. \frac{dy}{dx} = \tan t, \frac{d^2 y}{dx^2} = \frac{1}{at \cos^3 t}.
19. x = \frac{1 - t}{1 + t}, y = \frac{2t}{1 + t}.
20. x = 2 t, y = 2 - t^2.
21. x = 1 - t^2, y = t^3.
22. x = a \cos t, y = b \sin t.
23. Transform \frac{ x \frac{dy}{dx} - y}{ \sqrt{1 + \left( \frac{dy}{dx} \right)^2} } by assuming x = \rho \cos \theta, y = \rho \sin \theta.
  Ans. \frac{\rho^2}{ \sqrt{ \rho \left( \frac{d\rho}{d\theta} \right)^2 } }.
24. Let f(x, y) = 0 be the equation of a curve. Find an expression for its slope \left( \frac{dy}{dx} \right) in terms of polar coördinates.
  Ans. \frac{dy}{dx} = \frac{ \rho \cos \theta + \sin \theta \frac{d\rho}{d\theta} }{ -\rho \sin \theta + \cos \theta \frac{d\rho}{d\theta} }.