Page:Proceedings of the Royal Society of London Vol 69.djvu/492

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472
Dr. A. Findlay. On a Method of Calculating Solubilities,

Table I. Calculation of the Vapour Pressures of Carbon Disulphide from the Vapour Pressures of Water.

c = 0-0006568.

Ratios of

Pressures in mill.


Abs. temps, of water.


abs. temps, of CS 2 to those of


Smoothed ratios.


Re-calculated Observed abs. temps. abs. temps, of CS 2 . of CSj.




H 2 0.




50


311-3


-8161


-8160


254-0


254 -05


100


324-7


-8245


-8242


267-6


267-7


150


333-1


-8301


0-8296


276-3


276-5


200 339 '6


-8339


-8338


283-2


283-2


300 348 -9


-8403


0-8400


293-1


293-2


400 356 -0


0-8418


-8449


300-8


300 -75


500 361 ' 7


-8485


-8483


306-8


306-9


600


366-5


-8517


-8519


312-2


312-15


700 370 -7


-8545


-8545


316-8


316-75


800 374 -45


-8567


0-8571


320 -9


320-8


900 377 -8


-8589


-8590


324-5


324-5


1000


380 -85


0-8612 0-8611


327 -95


328-0


1500


393-2


-8695


-8692


341-8


341-9


2000


402-5


-8753 -8757


OOi "O


352 -3


3000


416-5-


-8852 -8850


368-6


368-7


5000


435 -85


0-8987


-8978


391 -3


391 7


ties; c is a constant which may, possibly, have the value 0, but which, in all the cases I have examined, has a small positive or negative value; t′ and t are the temperatures at which one of the substances has the two values of the solubility in question. The above equation also holds no matter whether the substances are ionised or are non-ionised, or whether their heat of solution is positive or negative.

A method, which is in all points analogous to that employed by Ramsay and Young[1] for the calculation of vapour pressures, can thus be made use of for the calculation of solubilities. In order to calculate the solubility of any substance B by means of the known values of the solubility of another substance A, one proceeds as follows: The solubility of B at any two absolute temperatures T′₁ and T′₂ is determined. On dividing these temperatures into the temperatures T₁ and T₂, at which A has the same solubility, the ratios T₁/T′ and T₂/T′₂ are obtained. These ratios are now plotted as abscissae against the corresponding temperatures of the substance A as ordinates, and a straight line drawn through the two points thus obtained. From this straight line curve, now, different ratios can be read off, and also the corresponding values of the absolute temperatures of substance A. By dividing the absolute temperature T of substance A by the corresponding value of the temperature ratio, the

  1. Loc. cit.