# Page:Scientific Memoirs, Vol. 3 (1843).djvu/691

 Columns on which are inscribed the primitive data. Number of the operations. Cards of the operations. Variable cards. Statement of results. Number of the Operation cards. Nature of each operation. Columns acted on by each operation. Columns that receive the result of each operation. Indication of change of value on any column. $^1V_0 = m$ 1 1 $\times$ $^1V_0 \times{} ^1V_4 =$ $^1V_6 \ldots \ldots$ \left \{ \begin{align} &^1V_0 ={} ^1V_0 \\ &^1V_4 = {}^1V_4\end{align} \right \} $^1V_6 = mn'$ $^1V_1 = n$ 2 " $\times$ $^1V_3 \times{} ^1V_1 =$ $^1V_7 \ldots \ldots$ \left \{ \begin{align} &^1V_3 ={} ^1V_3 \\ &^1V_1 = {}^1V_1\end{align} \right \} $^1V_7 = m'n$ $^1V_2 = d$ 3 " $\times$ $^1V_2 \times{} ^1V_4 =$ $^1V_8 \ldots \ldots$ \left \{ \begin{align} &^1V_2 ={} ^1V_2 \\ &^1V_4 = {}^0V_4\end{align} \right \} $^1V_8 = dn'$ $^1V_3 = m'$ 4 " $\times$ $^1V_5 \times{} ^1V_1 =$ $^1V_9 \ldots \ldots$ \left \{ \begin{align} &^1V_5 ={} ^1V_5 \\ &^1V_1 = {}^1V_1\end{align} \right \} $^1V_9 = d'n$ $^1V_4 = n'$ 5 " $\times$ $^1V_0 \times{} ^1V_5 =$ $^1V_{10} \ldots \ldots$ \left \{ \begin{align} &^1V_0 ={} ^0V_0 \\ &^1V_5 = {}^0V_5\end{align} \right \} $^1V_{10} = d'm$ $^1V_5 = d'$ 6 " $\times$ $^1V_2 \times{} ^1V_3 =$ $^1V_{11} \ldots \ldots$ \left \{ \begin{align} &^1V_2 ={} ^0V_2 \\ &^1V_3 = {}^0V_3\end{align} \right \} $^1V_{11} = dm'$ 7 2 ${}-{}$ $^1V_6 -{} ^1V_7 =$ $^1V_{12} \ldots \ldots$ \left \{ \begin{align} &^1V_6 ={} ^0V_6 \\ &^1V_7 = {}^0V_7\end{align} \right \} $^1V_{12} = mn'-m'n$ 8 " ${}-{}$ $^1V_8 -{} ^1V_9 =$ $^1V_{13} \ldots \ldots$ \left \{ \begin{align} &^1V_8 ={} ^0V_8 \\ &^1V_9 = {}^0V_9\end{align} \right \} $^1V_{13} = dn'-d'n$ 9 " ${}-{}$ $^1V_{10} - {} ^1V_{11} =$ $^1V_{14} \ldots \ldots$ \left \{ \begin{align} &^1V_{10} ={} ^0V_{10} \\ &^1V_{11} = {}^0V_{11}\end{align} \right \} $^1V_{14} = d'm - dm'$ 10 3 $\div$ $^1V_{13} \div {} ^1V_{12} =$ $^1V_{15} \ldots \ldots$ \left \{ \begin{align} &^1V_{13} ={} ^0V_{13} \\ &^1V_{12} = {}^1V_{12}\end{align} \right \} $^1V_{15} = \frac{{dn'-d'n}}{{mn' - m'n}} = x$ 11 " $\div$ $^1V_{14} - {} ^1V_{12} =$ $^1V_{16} \ldots \ldots$ \left \{ \begin{align} &^1V_{14} ={} ^0V_{14} \\ &^1V_{12} = {}^0V_{12}\end{align} \right \} $^1V_{16} = \frac{{d'm - dm'}}{{mn'-m'n}}=y$ 1 2 3 4 5 6 7 8