Page:Sheet Metal Drafting.djvu/137

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SECTIONS FORMED BY CUTTING PLANES
123

part of the handle to aid the hand in gripping it. The handle does not require a pattern since it is a straight strip of metal whose length is equal to the perimeter of the profile, Fig. 169, and whose width is equal to 1¼ in. plus the allowances for stiffening each side. The pattern of the boss is obtained in exactly the same manner as the pattern of the breast, and needs no further description. Figure 170 shows the profile of the S handle together with its boss. The pattern for the S handle is a tapering strip of metal whose length is equal to the distance around the profile, Fig. 170, and whose large end is 1¼ in. wide, while the small end is ⅝ in. wide. A ¼-inch wire edge is added to each side for the stiffening wire.

56. Related Mathematics on Sprinkling Can.Volume of Sprinkling Can.—In Chapter II it was learned that the volume of a cylinder is equal to the area of the base multiplied by the height, or V=A×H. It was also found that the area of a circle was equal to the diameter squared, multiplied by .7854, or D2×.7854.

Sprinkling cans are generally listed according to their holding capacity in gallons, quarts, and pints.

Sample Problem.—What is the capacity of a sprinkling can whose diameter is 8″ and whose height is 10½″?
Formula: V=D2 ×.7854 ×H
Substituting, V=82 ×.7854 ×10.5.
V=64 ×.7854 ×10.5.
.7854
64
 31416
47124 
50.2656
10.5
2513280
5026560 
527.78880 cu. in.

There are 231 cu. in. in one gallon; therefore,

231 527.789 2.28 gallons
462
 657 
 462
1958
 1848
 1109 Ans. 2.28 gal. or 9 qt.

But, 2.28 gallons is approximately 9 quarts, the extra contents being allowed for carrying nine full quarts without danger of spilling.