LAWS OF ELECTROLYTIC CONDUCTION
I chose such currents that a sufficient amount of silver was reduced before it began to drop off. When this threatened to occur the electrolysis was stopped.
Solution I
Specific gravity at 11.1° C.: 1.3079.
It contained 1 part NAg to 2.48 parts water.
The current reduced 1.2591 gr. Ag in 1½ hours at a temperature of 11.2° C.
The solution about the cathode gave:
Before electrolysis. . . 17.4624 gr. ClAg
After " . 16.6796 " "
It lost 0.7828 gr. ClAg, or 0.5893 gr. Ag.
Hence the amount of the transferred silver is
1.2591
−0.5893
6698
0.6698 gr., or 6698/12591=53.2 per cent.
Solution II
Specific gravity at 19.2° C.: 1.2788.
It contains 1 part NAg to 2.735 parts water.
The current from one cell reduced 1.909 gr. Ag at 19° C.
The solution at the cathode gave:
Before electrolysis. . . 15.9364 gr. ClAg
After " . 14.7233 " "
The loss is 1.2131 gr. ClAg, or 0.9132 gr. Ag.
The transference of silver is therefore
1.909
−0.9132
9958
0.9958 gr., or 9958/19090=52.2 per cent.
Solution III
Specific gravity at 18.4° C.: 1.1534.
It contains 1 part NAg to 5.18 parts water.
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