40
if 24h give 42', what will 6h 30m give?—Answer, 11' 20": ſubtract this from 7s 23° 49', the Longitude at noon on the second day, and the remainder is, 7s 23° 37' 40", the true Longitude of Mercury at the time required; then for the Latitude of the Planet, obſerve, on the firſt day it is 2° 16' South; and on the ſeventh day, 0° 38' South, and of courſe decreaſing: ſubtract, and the difference is 1° 38': then say, if ſix days give 1° 38', what will 1 day, 6h 30m give?—Answer, 20' 21', to be ſubtracted from the Latitude on the firſt day, 2° 16', and it leaves 1° 55' 39" for the true South Latitude of the Planet at the day and hour propoſed; ſeek theſe points in Longitude and Latitude in the Zodiac of the Planisphere, and that is the true and corrected place of Mercury for the time required, viz. in 7s 23° 37' 40", and between the Stars in the Scales, and the Claws of the Scorpion, and you may take the right Aſcenſion and Declination of the Planet at the time, as before taught; by this rule, we have the ſituation of all the Planets among the Stars at any time required, and by which, any perſon may learn to diſtinguiſh, and know them by ſight from the fixed Stars, and to trace their progreſſive motions continually.
FINIS.
Entered at Stationers Hall.
Kemmiſh, Printer, King-Street, Borough.
