If the curved surface is a sphere of radius
R
,
{\textstyle R,}
we shall have
α
=
β
=
γ
=
−
2
f
∘
=
1
R
2
;
f
″
=
0
,
g
′
=
0
,
6
h
∘
−
f
∘
2
=
0
,
{\displaystyle \alpha =\beta =\gamma =-2f^{\circ }={\frac {1}{R^{2}}};\quad f''=0,\quad g'=0,\quad 6h^{\circ }-{f^{\circ }}^{2}=0,}
or
h
∘
=
1
24
R
4
.
{\displaystyle h^{\circ }={\frac {1}{24R^{4}}}.}
Consequently, formula [14] becomes
A
+
B
+
C
=
π
+
σ
R
2
,
{\displaystyle A+B+C=\pi +{\frac {\sigma }{R^{2}}},}
which is absolutely exact. But formulæ [11], [12], [13] give
A
∗
=
A
−
σ
3
R
2
−
σ
180
R
4
(
2
p
2
−
q
2
+
4
q
q
′
−
q
′
2
)
B
∗
=
B
−
σ
3
R
2
+
σ
180
R
4
(
p
2
−
2
q
2
+
2
q
q
′
+
q
′
2
)
C
∗
=
C
−
σ
3
R
2
+
σ
180
R
4
(
p
2
+
q
2
+
2
q
q
′
−
2
q
′
2
)
{\displaystyle {\begin{aligned}A^{*}&=A-{\frac {\sigma }{3R^{2}}}-{\frac {\sigma }{180R^{4}}}(2p^{2}-q^{2}+4qq'-q'^{2})\\B^{*}&=B-{\frac {\sigma }{3R^{2}}}+{\frac {\sigma }{180R^{4}}}(p^{2}-2q^{2}+2qq'+q'^{2})\\C^{*}&=C-{\frac {\sigma }{3R^{2}}}+{\frac {\sigma }{180R^{4}}}(p^{2}+q^{2}+2qq'-2q'^{2})\end{aligned}}}
or, with equal exactness,
A
∗
=
A
−
σ
3
R
2
−
σ
180
R
4
(
b
2
+
c
2
−
2
a
2
)
B
∗
=
B
−
σ
3
R
2
−
σ
180
R
4
(
a
2
+
c
2
−
2
b
2
)
C
∗
=
C
−
σ
3
R
2
−
σ
180
R
4
(
a
2
+
b
2
−
2
c
2
)
{\displaystyle {\begin{aligned}A^{*}&=A-{\frac {\sigma }{3R^{2}}}-{\frac {\sigma }{180R^{4}}}(b^{2}+c^{2}-2a^{2})\\B^{*}&=B-{\frac {\sigma }{3R^{2}}}-{\frac {\sigma }{180R^{4}}}(a^{2}+c^{2}-2b^{2})\\C^{*}&=C-{\frac {\sigma }{3R^{2}}}-{\frac {\sigma }{180R^{4}}}(a^{2}+b^{2}-2c^{2})\end{aligned}}}
Neglecting quantities of the fourth order, we obtain from the above the well-known theorem first established by the illustrious Legendre.
Our general formulæ, if we neglect terms of the fourth order, become extremely simple, namely:
A
∗
=
A
−
1
12
σ
(
2
α
+
β
+
γ
)
B
∗
=
B
−
1
12
σ
(
α
+
2
β
+
γ
)
C
∗
=
C
−
1
12
σ
(
α
+
β
+
2
γ
)
{\displaystyle {\begin{aligned}A^{*}&=A-{\tfrac {1}{12}}\sigma (2\alpha +\beta +\gamma )\\B^{*}&=B-{\tfrac {1}{12}}\sigma (\alpha +2\beta +\gamma )\\C^{*}&=C-{\tfrac {1}{12}}\sigma (\alpha +\beta +2\gamma )\end{aligned}}}