emitted energy, or received energy. Fortunately, it’s only a trivial matter of algebraic manipulation to rearrange our last equation to solve for ${\displaystyle {\mbox{T}}_{\mbox{p}}}$:
 ${\displaystyle {\sqrt[{4}]{\tfrac {(S_{o}(1-\alpha )}{4\sigma }}}={\mbox{T}}_{\mbox{p}}}$ (4g)