Page:Zur Theorie der Strahlung in bewegten Körpern. Berichtigung.djvu/2

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electromagnetic momentum which coincides with the direction of the system and which is contained in the cavity, we have to calculate expression (1) with , then to integrate with respect to from O to , and then to multiply the result with the volume of cavity . If we additionally substitute for its value[1], then the momentum becomes

Now, the longitudinal electromagnetic mass is given by ;[2] thus it becomes equal to (when higher terms are neglected):

This is half of the value given by me.

After it was sought in vain after a principal difference, I found that this difference stems from a calculation error, unfortunately committed by me in my paper. At p. 362, line 6 from above,

not shall be stated, but ,

therefore the heat absorbed by the walls of the cavity when the system is accelerated, is:

however, since furthermore the walls have given off the heat , we can say that the walls of the cavity (when accelerated by ) have altogether given off the heat

  1. F. Hasenöhrl, l. c. p. 347, Equation (1).
  2. M. Abraham, Ann. d. Phys. 10. p. 150. (Gl. 16a) 1903.