Page:Zur Thermodynamik bewegter Systeme (Fortsetzung).djvu/6

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The energy content of the cavity is:

U=2\pi v\int_{0}^{\pi}\frac{J\sin\phi\ d\phi}{c'},

where c' means the relative velocity:


If we set in the previous integral according to (19):

J = i + J\beta\ \cos\varphi,

then it becomes:

U=2\pi v\int_{0}^{\pi}\frac{i\ \sin\phi\ d\phi}{c'}+2\pi v\beta\int_{0}^{\pi}\frac{J\cos\phi\ \sin\phi\ d\phi}{c'}.

The second summand is equal to:

q\cdot\frac{2\pi v}{c^{2}}\int_{0}^{\pi}\frac{J}{c'}\cdot c\ \cos\varphi\cdot\sin\phi\ d\phi=q\mathfrak{G},

as one can most simply recognize by comparison with the penultimate equation of p. 11 of my first report. In consequence of (2) it is therefore:

H=2\pi v\int_{0}^{\pi}\frac{i\ \sin\phi\ d\phi}{c'}.

The quantity H is thus identical with the energy of the true radiation, which was indeed to be expected. If we introduce i' and \phi' by means of (20) and (21), then


because c'\sqrt{1-\beta^{2}\sin^{2}\phi}=c(1-\beta\cos\varphi) (see F. Hasenöhrl, Ann. d. Phys., 15, p. 347, Gl. 7 [1904]). That the absolute radiation intensity is changing with direction proportional to (1-\beta \cos \varphi)^4, was already demonstrated by v. Mosengeil in another way (Ann. d. Phys., 22, p. 875, eq. 11 [1907]).