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$\scriptstyle {\frac {1}{2}}$

$\scriptstyle {\frac {1}{2}}$

$\scriptstyle {\frac {1}{2}}$ ${\frac {1}{2}}$ $\scriptstyle {\frac {1}{2}}$ ${\frac {1}{2}}$

A A B

${\begin{matrix}&\left({f \over 5}\right)&\left({f \over 7}\right)\\(1,0,35)&+&+\\(4,\pm 2,9)&&\end{matrix}}$

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${\begin{matrix}(5,0,7)&-&-\\(3,\pm 2,12)&&\end{matrix}}$

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	$\left({f \over 5}\right)$	$\left({f \over 7}\right)$
(1, 0, 35)	+	+
(4, ± 2, 9)
(5, 0, 7)	−	−
(3, ± 2, 12)

	$\left({f \over 5}\right)$	$\left({f \over 7}\right)$
(1, 0, 35) (4, ±2, 9)	+	+
(5, 0, 7) (3, ±2, 12)	−	−

	$\left({f \over 5}\right)$	$\left({f \over 7}\right)$
(1, 0, 35) (4, ±2, 9)	+	+
(5, 0, 7) (3, ±2, 12)	−	−

Tooltip Text

x, y, z; and let U be any polynomial of the same nature as X, Y, Z, T.
We  may  write U∼o (mod m, X, Y, Z, T) to express the fact that
there  are  integral polynomials M, X′, Y′, Z′, T′ such that

x, y, z; and let U be any polynomial of the same nature as X, Y, Z, T.
We  may  write U～o (mod m, X, Y, Z, T) to express the fact that
there  are  integral polynomials M, X′, Y′, Z′, T′ such that